52. Middle of the Linked List
18 Jul 2020 | Daily Algorithms
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
ListNode* middleNode(ListNode* head) {
ListNode* p = head;
ListNode* q = head;
int n = 0;
while(p)
{
n++;
p = p->next;
}
n = n/2;
for(int i =0; i<n; i ++)
{
q = q->next;
}
return q;
}
};
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
ListNode* middleNode(ListNode* head) {
ListNode* p = head;
ListNode* q = head;
int n = 0;
while(p)
{
n++;
p = p->next;
}
n = n/2;
for(int i =0; i<n; i ++)
{
q = q->next;
}
return q;
}
};
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